6(-3v-11)=8(4+10v)

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Solution for 6(-3v-11)=8(4+10v) equation: 



6(-3v-11)=8(4+10v)

We move all terms to the left:

6(-3v-11)-(8(4+10v))=0

We add all the numbers together, and all the variables

6(-3v-11)-(8(10v+4))=0

We multiply parentheses

-18v-(8(10v+4))-66=0



We calculate terms in parentheses: -(8(10v+4)), so:

8(10v+4)

We multiply parentheses

80v+32

Back to the equation:

-(80v+32)



We get rid of parentheses

-18v-80v-32-66=0

We add all the numbers together, and all the variables

-98v-98=0

We move all terms containing v to the left, all other terms to the right

-98v=98

v=98/-98

v=-1

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