6(-3v+1)=-(2v-2)

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Solution for 6(-3v+1)=-(2v-2) equation: 



6(-3v+1)=-(2v-2)

We move all terms to the left:

6(-3v+1)-(-(2v-2))=0

We multiply parentheses

-18v-(-(2v-2))+6=0



We calculate terms in parentheses: -(-(2v-2)), so:

-(2v-2)

We get rid of parentheses

-2v+2

Back to the equation:

-(-2v+2)



We get rid of parentheses

-18v+2v-2+6=0

We add all the numbers together, and all the variables

-16v+4=0

We move all terms containing v to the left, all other terms to the right

-16v=-4

v=-4/-16

v=1/4

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