6(-2z+3)=3(3z+6)

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Solution for 6(-2z+3)=3(3z+6) equation: 



6(-2z+3)=3(3z+6)

We move all terms to the left:

6(-2z+3)-(3(3z+6))=0

We multiply parentheses

-12z-(3(3z+6))+18=0



We calculate terms in parentheses: -(3(3z+6)), so:

3(3z+6)

We multiply parentheses

9z+18

Back to the equation:

-(9z+18)



We get rid of parentheses

-12z-9z-18+18=0

We add all the numbers together, and all the variables

-21z=0

z=0/-21

z=0

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