6(-17k-15)+10k=2(-47k-49)+4k

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Solution for 6(-17k-15)+10k=2(-47k-49)+4k equation: 



6(-17k-15)+10k=2(-47k-49)+4k

We move all terms to the left:

6(-17k-15)+10k-(2(-47k-49)+4k)=0

We add all the numbers together, and all the variables

10k+6(-17k-15)-(2(-47k-49)+4k)=0

We multiply parentheses

10k-102k-(2(-47k-49)+4k)-90=0



We calculate terms in parentheses: -(2(-47k-49)+4k), so:

2(-47k-49)+4k

We add all the numbers together, and all the variables

4k+2(-47k-49)

We multiply parentheses

4k-94k-98

We add all the numbers together, and all the variables

-90k-98

Back to the equation:

-(-90k-98)



We add all the numbers together, and all the variables

-92k-(-90k-98)-90=0

We get rid of parentheses

-92k+90k+98-90=0

We add all the numbers together, and all the variables

-2k+8=0

We move all terms containing k to the left, all other terms to the right

-2k=-8

k=-8/-2

k=+4

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