6((2-y)/6)+y=12

Solution for 6((2-y)/6)+y=12 equation:

6((2-y)/6)+y=12

We move all terms to the left:

6((2-y)/6)+y-(12)=0

We add all the numbers together, and all the variables

6((-1y+2)/6)+y-12=0

We add all the numbers together, and all the variables

y+6((-1y+2)/6)-12=0

We multiply all the terms by the denominator


y*6)+6((-1y+2)-12*6)=0

We add all the numbers together, and all the variables

y*6)+6((-1y+2)=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$