5z-2z+4z+16=3z+4(z+4)

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Solution for 5z-2z+4z+16=3z+4(z+4) equation:


Simplifying
5z + -2z + 4z + 16 = 3z + 4(z + 4)

Reorder the terms:
16 + 5z + -2z + 4z = 3z + 4(z + 4)

Combine like terms: 5z + -2z = 3z
16 + 3z + 4z = 3z + 4(z + 4)

Combine like terms: 3z + 4z = 7z
16 + 7z = 3z + 4(z + 4)

Reorder the terms:
16 + 7z = 3z + 4(4 + z)
16 + 7z = 3z + (4 * 4 + z * 4)
16 + 7z = 3z + (16 + 4z)

Reorder the terms:
16 + 7z = 16 + 3z + 4z

Combine like terms: 3z + 4z = 7z
16 + 7z = 16 + 7z

Add '-16' to each side of the equation.
16 + -16 + 7z = 16 + -16 + 7z

Combine like terms: 16 + -16 = 0
0 + 7z = 16 + -16 + 7z
7z = 16 + -16 + 7z

Combine like terms: 16 + -16 = 0
7z = 0 + 7z
7z = 7z

Add '-7z' to each side of the equation.
7z + -7z = 7z + -7z

Combine like terms: 7z + -7z = 0
0 = 7z + -7z

Combine like terms: 7z + -7z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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