5z+4-2z=3(z-1)

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Solution for 5z+4-2z=3(z-1) equation: 



5z+4-2z=3(z-1)

We move all terms to the left:

5z+4-2z-(3(z-1))=0

We add all the numbers together, and all the variables

3z-(3(z-1))+4=0



We calculate terms in parentheses: -(3(z-1)), so:

3(z-1)

We multiply parentheses

3z-3

Back to the equation:

-(3z-3)



We get rid of parentheses

3z-3z+3+4=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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