5z+35=4z-48

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Solution for 5z+35=4z-48 equation: 



5z+35=4z-48

We move all terms to the left:

5z+35-(4z-48)=0

We get rid of parentheses

5z-4z+48+35=0

We add all the numbers together, and all the variables

z+83=0

We move all terms containing z to the left, all other terms to the right

z=-83

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