5z+13+26z=51+29z-(-2)

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Solution for 5z+13+26z=51+29z-(-2) equation: 



5z+13+26z=51+29z-(-2)

We move all terms to the left:

5z+13+26z-(51+29z-(-2))=0

We add all the numbers together, and all the variables

31z-(51+29z-(-2))+13=0



We calculate terms in parentheses: -(51+29z-(-2)), so:

51+29z-(-2)

determiningTheFunctionDomain
29z+51-(-2)

We add all the numbers together, and all the variables

29z+53

Back to the equation:

-(29z+53)



We get rid of parentheses

31z-29z-53+13=0

We add all the numbers together, and all the variables

2z-40=0

We move all terms containing z to the left, all other terms to the right

2z=40

z=40/2

z=20

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