5z+100=3z+112

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Solution for 5z+100=3z+112 equation: 



5z+100=3z+112

We move all terms to the left:

5z+100-(3z+112)=0

We get rid of parentheses

5z-3z-112+100=0

We add all the numbers together, and all the variables

2z-12=0

We move all terms containing z to the left, all other terms to the right

2z=12

z=12/2

z=6

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