5z(6z-7)=

Solution for 5z(6z-7)= equation:

5z(6z-7)=

We move all terms to the left:

5z(6z-7)-()=0

We add all the numbers together, and all the variables

5z(6z-7)=0

We multiply parentheses

30z^2-35z=0

a = 30; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·30·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*30}=\frac{0}{60}
=0
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*30}=\frac{70}{60}
=1+1/6
$