5y=7+3(2y-1)

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Solution for 5y=7+3(2y-1) equation: 



5y=7+3(2y-1)

We move all terms to the left:

5y-(7+3(2y-1))=0



We calculate terms in parentheses: -(7+3(2y-1)), so:

7+3(2y-1)

determiningTheFunctionDomain
3(2y-1)+7

We multiply parentheses

6y-3+7

We add all the numbers together, and all the variables

6y+4

Back to the equation:

-(6y+4)



We get rid of parentheses

5y-6y-4=0

We add all the numbers together, and all the variables

-1y-4=0

We move all terms containing y to the left, all other terms to the right

-y=4

y=4/-1

y=-4

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