5y2=0.7y+0.45

Solution for 5y2=0.7y+0.45 equation:

5y^2=0.7y+0.45

We move all terms to the left:

5y^2-(0.7y+0.45)=0

We get rid of parentheses

5y^2-0.7y-0.45=0

a = 5; b = -0.7; c = -0.45;
Δ = b2-4ac
Δ = -0.72-4·5·(-0.45)
Δ = 9.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.7)-\sqrt{9.49}}{2*5}=\frac{0.7-\sqrt{9.49}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.7)+\sqrt{9.49}}{2*5}=\frac{0.7+\sqrt{9.49}}{10}
$