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5y^2-7y+1=0
a = 5; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·5·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{29}}{2*5}=\frac{7-\sqrt{29}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{29}}{2*5}=\frac{7+\sqrt{29}}{10} $
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