5y2+5y-560=0

Solution for 5y2+5y-560=0 equation:

5y^2+5y-560=0

a = 5; b = 5; c = -560;
Δ = b2-4ac
Δ = 52-4·5·(-560)
Δ = 11225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11225}=\sqrt{25*449}=\sqrt{25}*\sqrt{449}=5\sqrt{449}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{449}}{2*5}=\frac{-5-5\sqrt{449}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{449}}{2*5}=\frac{-5+5\sqrt{449}}{10}
$