5y-7+y=(4+3y)

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Solution for 5y-7+y=(4+3y) equation: 



5y-7+y=(4+3y)

We move all terms to the left:

5y-7+y-((4+3y))=0

We add all the numbers together, and all the variables

5y+y-((3y+4))-7=0

We add all the numbers together, and all the variables

6y-((3y+4))-7=0



We calculate terms in parentheses: -((3y+4)), so:

(3y+4)

We get rid of parentheses

3y+4

Back to the equation:

-(3y+4)



We get rid of parentheses

6y-3y-4-7=0

We add all the numbers together, and all the variables

3y-11=0

We move all terms containing y to the left, all other terms to the right

3y=11

y=11/3

y=3+2/3

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