5y-5=2(y+1)+3y-7

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Solution for 5y-5=2(y+1)+3y-7 equation:


Simplifying
5y + -5 = 2(y + 1) + 3y + -7

Reorder the terms:
-5 + 5y = 2(y + 1) + 3y + -7

Reorder the terms:
-5 + 5y = 2(1 + y) + 3y + -7
-5 + 5y = (1 * 2 + y * 2) + 3y + -7
-5 + 5y = (2 + 2y) + 3y + -7

Reorder the terms:
-5 + 5y = 2 + -7 + 2y + 3y

Combine like terms: 2 + -7 = -5
-5 + 5y = -5 + 2y + 3y

Combine like terms: 2y + 3y = 5y
-5 + 5y = -5 + 5y

Add '5' to each side of the equation.
-5 + 5 + 5y = -5 + 5 + 5y

Combine like terms: -5 + 5 = 0
0 + 5y = -5 + 5 + 5y
5y = -5 + 5 + 5y

Combine like terms: -5 + 5 = 0
5y = 0 + 5y
5y = 5y

Add '-5y' to each side of the equation.
5y + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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