5y-3=7(y-3)-2

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Solution for 5y-3=7(y-3)-2 equation:



5y-3=7(y-3)-2
We move all terms to the left:
5y-3-(7(y-3)-2)=0
We calculate terms in parentheses: -(7(y-3)-2), so:
7(y-3)-2
We multiply parentheses
7y-21-2
We add all the numbers together, and all the variables
7y-23
Back to the equation:
-(7y-23)
We get rid of parentheses
5y-7y+23-3=0
We add all the numbers together, and all the variables
-2y+20=0
We move all terms containing y to the left, all other terms to the right
-2y=-20
y=-20/-2
y=+10

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