5y-3=4+y2

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Solution for 5y-3=4+y2 equation: 



5y-3=4+y2

We move all terms to the left:

5y-3-(4+y2)=0

We add all the numbers together, and all the variables

-(+y^2+4)+5y-3=0

We get rid of parentheses

-y^2+5y-4-3=0

We add all the numbers together, and all the variables

-1y^2+5y-7=0

a = -1; b = 5; c = -7;
Δ = b2-4ac
Δ = 52-4·(-1)·(-7)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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