5y-3=4(y-2)

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Solution for 5y-3=4(y-2) equation: 



5y-3=4(y-2)

We move all terms to the left:

5y-3-(4(y-2))=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

5y-4y+8-3=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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