5y-3+2(5y+1)=-3(y+5)

Solution for 5y-3+2(5y+1)=-3(y+5) equation:

5y-3+2(5y+1)=-3(y+5)

We move all terms to the left:

5y-3+2(5y+1)-(-3(y+5))=0

We multiply parentheses

5y+10y-(-3(y+5))+2-3=0


We calculate terms in parentheses: -(-3(y+5)), so:

-3(y+5)

We multiply parentheses

-3y-15

Back to the equation:

-(-3y-15)


We add all the numbers together, and all the variables

15y-(-3y-15)-1=0

We get rid of parentheses

15y+3y+15-1=0

We add all the numbers together, and all the variables

18y+14=0

We move all terms containing y to the left, all other terms to the right

18y=-14

y=-14/18

y=-7/9