5y-3(y+2)=-4(z+1)

Solution for 5y-3(y+2)=-4(z+1) equation:

Simplifying
5y + -3(y + 2) = -4(z + 1)

Reorder the terms:
5y + -3(2 + y) = -4(z + 1)
5y + (2 * -3 + y * -3) = -4(z + 1)
5y + (-6 + -3y) = -4(z + 1)

Reorder the terms:
-6 + 5y + -3y = -4(z + 1)

Combine like terms: 5y + -3y = 2y
-6 + 2y = -4(z + 1)

Reorder the terms:
-6 + 2y = -4(1 + z)
-6 + 2y = (1 * -4 + z * -4)
-6 + 2y = (-4 + -4z)

Solving
-6 + 2y = -4 + -4z

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 2y = -4 + 6 + -4z

Combine like terms: -6 + 6 = 0
0 + 2y = -4 + 6 + -4z
2y = -4 + 6 + -4z

Combine like terms: -4 + 6 = 2
2y = 2 + -4z

Divide each side by '2'.
y = 1 + -2z

Simplifying
y = 1 + -2z