5y-2+3(2y+1)=-3(y+5)

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Solution for 5y-2+3(2y+1)=-3(y+5) equation: 



5y-2+3(2y+1)=-3(y+5)

We move all terms to the left:

5y-2+3(2y+1)-(-3(y+5))=0

We multiply parentheses

5y+6y-(-3(y+5))+3-2=0



We calculate terms in parentheses: -(-3(y+5)), so:

-3(y+5)

We multiply parentheses

-3y-15

Back to the equation:

-(-3y-15)



We add all the numbers together, and all the variables

11y-(-3y-15)+1=0

We get rid of parentheses

11y+3y+15+1=0

We add all the numbers together, and all the variables

14y+16=0

We move all terms containing y to the left, all other terms to the right

14y=-16

y=-16/14

y=-1+1/7

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