5y-2(y+8)=2y-3(3y-8)

Solution for 5y-2(y+8)=2y-3(3y-8) equation:

5y-2(y+8)=2y-3(3y-8)

We move all terms to the left:

5y-2(y+8)-(2y-3(3y-8))=0

We multiply parentheses

5y-2y-(2y-3(3y-8))-16=0


We calculate terms in parentheses: -(2y-3(3y-8)), so:

2y-3(3y-8)

We multiply parentheses

2y-9y+24

We add all the numbers together, and all the variables

-7y+24

Back to the equation:

-(-7y+24)


We add all the numbers together, and all the variables

3y-(-7y+24)-16=0

We get rid of parentheses

3y+7y-24-16=0

We add all the numbers together, and all the variables

10y-40=0

We move all terms containing y to the left, all other terms to the right

10y=40

y=40/10

y=4