5y-2(y+5)=(-2y+15)+y

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Solution for 5y-2(y+5)=(-2y+15)+y equation: 



5y-2(y+5)=(-2y+15)+y

We move all terms to the left:

5y-2(y+5)-((-2y+15)+y)=0

We multiply parentheses

5y-2y-((-2y+15)+y)-10=0



We calculate terms in parentheses: -((-2y+15)+y), so:

(-2y+15)+y

We add all the numbers together, and all the variables

y+(-2y+15)

We get rid of parentheses

y-2y+15

We add all the numbers together, and all the variables

-1y+15

Back to the equation:

-(-1y+15)



We add all the numbers together, and all the variables

3y-(-1y+15)-10=0

We get rid of parentheses

3y+1y-15-10=0

We add all the numbers together, and all the variables

4y-25=0

We move all terms containing y to the left, all other terms to the right

4y=25

y=25/4

y=6+1/4

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