5y-2(3-y)=4(1+y)+3y-10

Solution for 5y-2(3-y)=4(1+y)+3y-10 equation:

Simplifying
5y + -2(3 + -1y) = 4(1 + y) + 3y + -10
5y + (3 * -2 + -1y * -2) = 4(1 + y) + 3y + -10
5y + (-6 + 2y) = 4(1 + y) + 3y + -10

Reorder the terms:
-6 + 5y + 2y = 4(1 + y) + 3y + -10

Combine like terms: 5y + 2y = 7y
-6 + 7y = 4(1 + y) + 3y + -10
-6 + 7y = (1 * 4 + y * 4) + 3y + -10
-6 + 7y = (4 + 4y) + 3y + -10

Reorder the terms:
-6 + 7y = 4 + -10 + 4y + 3y

Combine like terms: 4 + -10 = -6
-6 + 7y = -6 + 4y + 3y

Combine like terms: 4y + 3y = 7y
-6 + 7y = -6 + 7y

Add '6' to each side of the equation.
-6 + 6 + 7y = -6 + 6 + 7y

Combine like terms: -6 + 6 = 0
0 + 7y = -6 + 6 + 7y
7y = -6 + 6 + 7y

Combine like terms: -6 + 6 = 0
7y = 0 + 7y
7y = 7y

Add '-7y' to each side of the equation.
7y + -7y = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.