5y-2(3+y)=2(1y-2)-10

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Solution for 5y-2(3+y)=2(1y-2)-10 equation:


Simplifying
5y + -2(3 + y) = 2(1y + -2) + -10
5y + (3 * -2 + y * -2) = 2(1y + -2) + -10
5y + (-6 + -2y) = 2(1y + -2) + -10

Reorder the terms:
-6 + 5y + -2y = 2(1y + -2) + -10

Combine like terms: 5y + -2y = 3y
-6 + 3y = 2(1y + -2) + -10

Reorder the terms:
-6 + 3y = 2(-2 + 1y) + -10
-6 + 3y = (-2 * 2 + 1y * 2) + -10
-6 + 3y = (-4 + 2y) + -10

Reorder the terms:
-6 + 3y = -4 + -10 + 2y

Combine like terms: -4 + -10 = -14
-6 + 3y = -14 + 2y

Solving
-6 + 3y = -14 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-6 + 3y + -2y = -14 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-6 + 1y = -14 + 2y + -2y

Combine like terms: 2y + -2y = 0
-6 + 1y = -14 + 0
-6 + 1y = -14

Add '6' to each side of the equation.
-6 + 6 + 1y = -14 + 6

Combine like terms: -6 + 6 = 0
0 + 1y = -14 + 6
1y = -14 + 6

Combine like terms: -14 + 6 = -8
1y = -8

Divide each side by '1'.
y = -8

Simplifying
y = -8

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