5y-1+y+41=8y+40-4y

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Solution for 5y-1+y+41=8y+40-4y equation: 



5y-1+y+41=8y+40-4y

We move all terms to the left:

5y-1+y+41-(8y+40-4y)=0

We add all the numbers together, and all the variables

5y+y-(4y+40)-1+41=0

We add all the numbers together, and all the variables

6y-(4y+40)+40=0

We get rid of parentheses

6y-4y-40+40=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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