5y-1+y+35=7y+40-4y

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Solution for 5y-1+y+35=7y+40-4y equation: 



5y-1+y+35=7y+40-4y

We move all terms to the left:

5y-1+y+35-(7y+40-4y)=0

We add all the numbers together, and all the variables

5y+y-(3y+40)-1+35=0

We add all the numbers together, and all the variables

6y-(3y+40)+34=0

We get rid of parentheses

6y-3y-40+34=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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