5y-(3y-2)=4(y-3)

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Solution for 5y-(3y-2)=4(y-3) equation: 



5y-(3y-2)=4(y-3)

We move all terms to the left:

5y-(3y-2)-(4(y-3))=0

We get rid of parentheses

5y-3y-(4(y-3))+2=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

2y-(4y-12)+2=0

We get rid of parentheses

2y-4y+12+2=0

We add all the numbers together, and all the variables

-2y+14=0

We move all terms containing y to the left, all other terms to the right

-2y=-14

y=-14/-2

y=+7

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