5y-(2y-9)=6+(y+3)

Solution for 5y-(2y-9)=6+(y+3) equation:

5y-(2y-9)=6+(y+3)

We move all terms to the left:

5y-(2y-9)-(6+(y+3))=0

We get rid of parentheses

5y-2y-(6+(y+3))+9=0


We calculate terms in parentheses: -(6+(y+3)), so:

6+(y+3)

determiningTheFunctionDomain
(y+3)+6

We get rid of parentheses

y+3+6

We add all the numbers together, and all the variables

y+9

Back to the equation:

-(y+9)


We add all the numbers together, and all the variables

3y-(y+9)+9=0

We get rid of parentheses

3y-y-9+9=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0