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5y+5=7+3(y+4)
We move all terms to the left:
5y+5-(7+3(y+4))=0
We calculate terms in parentheses: -(7+3(y+4)), so:We get rid of parentheses
7+3(y+4)
determiningTheFunctionDomain 3(y+4)+7
We multiply parentheses
3y+12+7
We add all the numbers together, and all the variables
3y+19
Back to the equation:
-(3y+19)
5y-3y-19+5=0
We add all the numbers together, and all the variables
2y-14=0
We move all terms containing y to the left, all other terms to the right
2y=14
y=14/2
y=7
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