5y+4(y+7)=3(y+2)-3

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Solution for 5y+4(y+7)=3(y+2)-3 equation:



5y+4(y+7)=3(y+2)-3
We move all terms to the left:
5y+4(y+7)-(3(y+2)-3)=0
We multiply parentheses
5y+4y-(3(y+2)-3)+28=0
We calculate terms in parentheses: -(3(y+2)-3), so:
3(y+2)-3
We multiply parentheses
3y+6-3
We add all the numbers together, and all the variables
3y+3
Back to the equation:
-(3y+3)
We add all the numbers together, and all the variables
9y-(3y+3)+28=0
We get rid of parentheses
9y-3y-3+28=0
We add all the numbers together, and all the variables
6y+25=0
We move all terms containing y to the left, all other terms to the right
6y=-25
y=-25/6
y=-4+1/6

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