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5y+3/2y+1=2/5
We move all terms to the left:
5y+3/2y+1-(2/5)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
5y+3/2y+1-(+2/5)=0
We get rid of parentheses
5y+3/2y+1-2/5=0
We calculate fractions
There is no solution for this equation
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