5y+3(y-2)=5(y+1)-3

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Solution for 5y+3(y-2)=5(y+1)-3 equation: 



5y+3(y-2)=5(y+1)-3

We move all terms to the left:

5y+3(y-2)-(5(y+1)-3)=0

We multiply parentheses

5y+3y-(5(y+1)-3)-6=0



We calculate terms in parentheses: -(5(y+1)-3), so:

5(y+1)-3

We multiply parentheses

5y+5-3

We add all the numbers together, and all the variables

5y+2

Back to the equation:

-(5y+2)



We add all the numbers together, and all the variables

8y-(5y+2)-6=0

We get rid of parentheses

8y-5y-2-6=0

We add all the numbers together, and all the variables

3y-8=0

We move all terms containing y to the left, all other terms to the right

3y=8

y=8/3

y=2+2/3

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