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5y+2=(1)/(2)(16y-4)
We move all terms to the left:
5y+2-((1)/(2)(16y-4))=0
Domain of the equation: 2(16y-4))!=0We multiply all the terms by the denominator
y∈R
5y*2(16y-4))-(1+2*2(16y-4))=0
Wy multiply elements
10y^2(1+4y(1=0
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