5y+2-4(-4y-1)=3(y-2)

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Solution for 5y+2-4(-4y-1)=3(y-2) equation: 



5y+2-4(-4y-1)=3(y-2)

We move all terms to the left:

5y+2-4(-4y-1)-(3(y-2))=0

We multiply parentheses

5y+16y-(3(y-2))+4+2=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We add all the numbers together, and all the variables

21y-(3y-6)+6=0

We get rid of parentheses

21y-3y+6+6=0

We add all the numbers together, and all the variables

18y+12=0

We move all terms containing y to the left, all other terms to the right

18y=-12

y=-12/18

y=-2/3

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