5y+2(y-3)=4(y+1)-2

Solution for 5y+2(y-3)=4(y+1)-2 equation:

Simplifying
5y + 2(y + -3) = 4(y + 1) + -2

Reorder the terms:
5y + 2(-3 + y) = 4(y + 1) + -2
5y + (-3 * 2 + y * 2) = 4(y + 1) + -2
5y + (-6 + 2y) = 4(y + 1) + -2

Reorder the terms:
-6 + 5y + 2y = 4(y + 1) + -2

Combine like terms: 5y + 2y = 7y
-6 + 7y = 4(y + 1) + -2

Reorder the terms:
-6 + 7y = 4(1 + y) + -2
-6 + 7y = (1 * 4 + y * 4) + -2
-6 + 7y = (4 + 4y) + -2

Reorder the terms:
-6 + 7y = 4 + -2 + 4y

Combine like terms: 4 + -2 = 2
-6 + 7y = 2 + 4y

Solving
-6 + 7y = 2 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-6 + 7y + -4y = 2 + 4y + -4y

Combine like terms: 7y + -4y = 3y
-6 + 3y = 2 + 4y + -4y

Combine like terms: 4y + -4y = 0
-6 + 3y = 2 + 0
-6 + 3y = 2

Add '6' to each side of the equation.
-6 + 6 + 3y = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 3y = 2 + 6
3y = 2 + 6

Combine like terms: 2 + 6 = 8
3y = 8

Divide each side by '3'.
y = 2.666666667

Simplifying
y = 2.666666667