5y+2(3y-1)=1y-(y+2)

Solution for 5y+2(3y-1)=1y-(y+2) equation:

Simplifying
5y + 2(3y + -1) = 1y + -1(y + 2)

Reorder the terms:
5y + 2(-1 + 3y) = 1y + -1(y + 2)
5y + (-1 * 2 + 3y * 2) = 1y + -1(y + 2)
5y + (-2 + 6y) = 1y + -1(y + 2)

Reorder the terms:
-2 + 5y + 6y = 1y + -1(y + 2)

Combine like terms: 5y + 6y = 11y
-2 + 11y = 1y + -1(y + 2)

Reorder the terms:
-2 + 11y = 1y + -1(2 + y)
-2 + 11y = 1y + (2 * -1 + y * -1)
-2 + 11y = 1y + (-2 + -1y)

Reorder the terms:
-2 + 11y = -2 + 1y + -1y

Combine like terms: 1y + -1y = 0
-2 + 11y = -2 + 0
-2 + 11y = -2

Add '2' to each side of the equation.
-2 + 2 + 11y = -2 + 2

Combine like terms: -2 + 2 = 0
0 + 11y = -2 + 2
11y = -2 + 2

Combine like terms: -2 + 2 = 0
11y = 0

Solving
11y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '11'.
y = 0

Simplifying
y = 0