5y+12+4y=3(3y+4)

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Solution for 5y+12+4y=3(3y+4) equation:


Simplifying
5y + 12 + 4y = 3(3y + 4)

Reorder the terms:
12 + 5y + 4y = 3(3y + 4)

Combine like terms: 5y + 4y = 9y
12 + 9y = 3(3y + 4)

Reorder the terms:
12 + 9y = 3(4 + 3y)
12 + 9y = (4 * 3 + 3y * 3)
12 + 9y = (12 + 9y)

Add '-12' to each side of the equation.
12 + -12 + 9y = 12 + -12 + 9y

Combine like terms: 12 + -12 = 0
0 + 9y = 12 + -12 + 9y
9y = 12 + -12 + 9y

Combine like terms: 12 + -12 = 0
9y = 0 + 9y
9y = 9y

Add '-9y' to each side of the equation.
9y + -9y = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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