5y(y+7)=

Solution for 5y(y+7)= equation:

5y(y+7)=

We move all terms to the left:

5y(y+7)-()=0

We add all the numbers together, and all the variables

5y(y+7)=0

We multiply parentheses

5y^2+35y=0

a = 5; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·5·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*5}=\frac{-70}{10}
=-7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*5}=\frac{0}{10}
=0
$