5y(6+3/5)=y+18

Solution for 5y(6+3/5)=y+18 equation:

5y(6+3/5)=y+18

We move all terms to the left:

5y(6+3/5)-(y+18)=0

We add all the numbers together, and all the variables

5y(3/5+6)-(y+18)=0

We multiply parentheses

15y^2+30y-(y+18)=0

We get rid of parentheses

15y^2+30y-y-18=0

We add all the numbers together, and all the variables

15y^2+29y-18=0

a = 15; b = 29; c = -18;
Δ = b2-4ac
Δ = 292-4·15·(-18)
Δ = 1921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{1921}}{2*15}=\frac{-29-\sqrt{1921}}{30}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{1921}}{2*15}=\frac{-29+\sqrt{1921}}{30}
$