5y(2-10)(20y+5)=25

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Solution for 5y(2-10)(20y+5)=25 equation: 



5y(2-10)(20y+5)=25

We move all terms to the left:

5y(2-10)(20y+5)-(25)=0

We add all the numbers together, and all the variables

5y(-8)(20y+5)-25=0

We multiply parentheses ..

5y(-160y-40)-25=0

We multiply parentheses

-800y^2-200y-25=0

a = -800; b = -200; c = -25;
Δ = b2-4ac
Δ = -2002-4·(-800)·(-25)
Δ = -40000
Delta is less than zero, so there is no solution for the equation

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