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5x^2=x+7
We move all terms to the left:
5x^2-(x+7)=0
We get rid of parentheses
5x^2-x-7=0
We add all the numbers together, and all the variables
5x^2-1x-7=0
a = 5; b = -1; c = -7;
Δ = b2-4ac
Δ = -12-4·5·(-7)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{141}}{2*5}=\frac{1-\sqrt{141}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{141}}{2*5}=\frac{1+\sqrt{141}}{10} $
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