If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2=804
We move all terms to the left:
5x^2-(804)=0
a = 5; b = 0; c = -804;
Δ = b2-4ac
Δ = 02-4·5·(-804)
Δ = 16080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16080}=\sqrt{16*1005}=\sqrt{16}*\sqrt{1005}=4\sqrt{1005}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1005}}{2*5}=\frac{0-4\sqrt{1005}}{10} =-\frac{4\sqrt{1005}}{10} =-\frac{2\sqrt{1005}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1005}}{2*5}=\frac{0+4\sqrt{1005}}{10} =\frac{4\sqrt{1005}}{10} =\frac{2\sqrt{1005}}{5} $
| 4(x-2)-5(x+3)=10 | | y/14+17=20 | | 147=3x-30 | | 15+4x=3x-6 | | 3(x-8)=5x+12* | | 63=x+31 | | 8+10-3y=-10y-10 | | –11+2a=7 | | 4/x=-9/11 | | 3+10-12=40x-5 | | 3/7=x/15 | | (5x+3*70)/8=67 | | z/9+9=−60 | | 3b+2=56 | | -5a-34=14-a | | 2/3=x-2/3 | | 90=14a | | -9v-7=7-7v | | 7(s−80)=84 | | 25=8+d | | r/4−1=2 | | 180=(13x-42)+(7x+22) | | k2+8=21 | | -2x^2-17x=-30 | | 4n+8=-60 | | 10=x/5=5 | | -2(r=9)=-35 | | 3p=-6-7p | | 3=-5+7w-9w | | 10=x/5=6 | | 2(3x+2)+4x=14 | | 2x+2=-3x+12 |