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5x^2=3x+14
We move all terms to the left:
5x^2-(3x+14)=0
We get rid of parentheses
5x^2-3x-14=0
a = 5; b = -3; c = -14;
Δ = b2-4ac
Δ = -32-4·5·(-14)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-17}{2*5}=\frac{-14}{10} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+17}{2*5}=\frac{20}{10} =2 $
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