5x2-x4/10

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Solution for 5x2-x4/10 equation: 


x in (-oo:+oo)

5*x^2-((x^4)/10) = 0

5*x^2-1/10*x^4 = 0

t_1 = x^2

5*t_1^1-1/10*t_1^2 = 0

5*t_1-1/10*t_1^2 = 0

DELTA = 5^2-(-1/10*0*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)-5)/(-1/10*2) or t_1 = (-25^(1/2)-5)/(-1/10*2)

t_1 = 0 or t_1 = 50

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

t_1 = 50

x^2-50 = 0

1*x^2 = 50 // : 1

x^2 = 50

x^2 = 50 // ^ 1/2

abs(x) = 5*2^(1/2)

x = 5*2^(1/2) or x = -(5*2^(1/2))

x in { 0, 5*2^(1/2), -(5*2^(1/2)) }

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