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5x^2-40x=5x
We move all terms to the left:
5x^2-40x-(5x)=0
We add all the numbers together, and all the variables
5x^2-45x=0
a = 5; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·5·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*5}=\frac{0}{10} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*5}=\frac{90}{10} =9 $
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