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5x^2-132x-132=0
a = 5; b = -132; c = -132;
Δ = b2-4ac
Δ = -1322-4·5·(-132)
Δ = 20064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20064}=\sqrt{16*1254}=\sqrt{16}*\sqrt{1254}=4\sqrt{1254}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-4\sqrt{1254}}{2*5}=\frac{132-4\sqrt{1254}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+4\sqrt{1254}}{2*5}=\frac{132+4\sqrt{1254}}{10} $
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