If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-11x=0
a = 5; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·5·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*5}=\frac{0}{10} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*5}=\frac{22}{10} =2+1/5 $
| 21=w^2+2.5w | | 42v=-4v+38 | | 10+j(2j)=130 | | 7=8b+11-4 | | -8(m-1)+6m=24-4m | | 12-2.2ss=4 | | 7=x+9-3x | | 6x+12(-11x+8)=10(10(x-4) | | 6x+2/x=3 | | 3(5x+1)=2x+20 | | 5(1-5x)+2x=189 | | x^2/(0.75-x)=0 | | 2r^2+7r+1.5=0 | | 3x÷12=x+16 | | 7x+9=2x+64 | | 4(m+3)-2m=3m(m-3) | | 432/(x-10)=-24 | | 8x^(2/3)-39x^(1/3)-5=0 | | 8-2v=-10 | | 19=x/16 | | 5(v+4)+7v=-16+3v | | 3x+(6x+8)=17 | | 100=-20r | | x+x/1.03=493.16 | | n/18=-10 | | 5n-8+2n=13 | | -9-3n=-6n+3(3-5n) | | 3x^2-26x-48=0 | | 13-2q=1+Q | | k/14=7 | | |5u-10|=15 | | (x-14)/7=12 |